With makeup conductivity of 390 micromhos, feedwater conductivity 180, and condensate conductivity 45, what is the condensate return percentage using CR = (MC - FC) / (MC - RC) × 100?

With makeup conductivity of 390 micromhos, feedwater conductivity 180, and condensate conductivity 45, what is the condensate return percentage using CR = (MC - FC) / (MC - RC) × 100?

• A. 60.9%
• B. 39%
• C. 72%
• D. 88%

Answer: (A)

This question tests applying the condensate return percentage formula CR = (MC - FC) / (MC - RC) × 100 using conductivity values. Plugging in MC = 390, FC = 180, RC = 45: MC - FC = 390 - 180 = 210 MC - RC = 390 - 45 = 345 CR = 210 / 345 × 100 ≈ 0.6087 × 100 = 60.9% So about 60.9% of makeup water is returned as condensate. The result follows directly from the given values; with these numbers the calculation yields 60.9%, not the other percentages.

This question tests applying the condensate return percentage formula CR = (MC - FC) / (MC - RC) × 100 using conductivity values.

Plugging in MC = 390, FC = 180, RC = 45:

MC - FC = 390 - 180 = 210

MC - RC = 390 - 45 = 345

CR = 210 / 345 × 100 ≈ 0.6087 × 100 = 60.9%

So about 60.9% of makeup water is returned as condensate. The result follows directly from the given values; with these numbers the calculation yields 60.9%, not the other percentages.